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JEE Advanced 2009 · Vector Algebra

If a⃗,b⃗,c⃗\vec{a}, \vec{b}, \vec{c} and d⃗\vec{d} are unit vectors such that (a⃗×b⃗)⋅(c⃗×d⃗)=1(\vec{a} \times \vec{b}) \cdot (\vec{c} \times \vec{d}) = 1 and a⃗⋅c⃗=12\vec{a} \cdot \vec{c} = \frac{1}{2}, then

Answer: C. b⃗,d⃗\vec{b}, \vec{d} are non-parallel

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Given: ∣a⃗∣=∣b⃗∣=∣c⃗∣=∣d⃗∣=1\text{Given: } |\vec{a}| = |\vec{b}| = |\vec{c}| = |\vec{d}| = 1 (a⃗×b⃗)⋅(c⃗×d⃗)=1(\vec{a} \times \vec{b}) \cdot (\vec{c} \times \vec{d}) = 1 a⃗⋅c⃗=12\vec{a} \cdot \vec{c} = \dfrac{1}{2} To find: which statement is correct?\text{To find: which statement is correct?} (1) a⃗,b⃗,c⃗ non-coplanar(2) b⃗,c⃗,d⃗ non-coplanar(1)\ \vec{a},\vec{b},\vec{c}\ \text{non-coplanar} \qquad (2)\ \vec{b},\vec{c},\vec{d}\ \text{non-coplanar} (3) b⃗,d⃗ non-parallel(4) a⃗∥d⃗, b⃗∥c⃗(3)\ \vec{b},\vec{d}\ \text{non-parallel} \qquad (4)\ \vec{a}\parallel\vec{d},\ \vec{b}\parallel\vec{c} Plan: 1. ∣a⃗×b⃗∣, ∣c⃗×d⃗∣≤1\text{Plan: } 1.\ |\vec{a} \times \vec{b}|,\ |\vec{c} \times \vec{d}| \le 1 2. a⃗×b⃗=c⃗×d⃗⇒a⃗,b⃗,c⃗,d⃗ coplanar2.\ \vec{a} \times \vec{b} = \vec{c} \times \vec{d} \Rightarrow \vec{a},\vec{b},\vec{c},\vec{d} \text{ coplanar} 3. Check each option3.\ \text{Check each option} ∣a⃗×b⃗∣=∣a⃗∣∣b⃗∣sin⁡θ=sin⁡θ≤1|\vec{a} \times \vec{b}| = |\vec{a}||\vec{b}|\sin\theta = \sin\theta \le 1 ∣c⃗×d⃗∣=sin⁡ϕ≤1|\vec{c} \times \vec{d}| = \sin\phi \le 1 (a⃗×b⃗)⋅(c⃗×d⃗)=∣a⃗×b⃗∣ ∣c⃗×d⃗∣cos⁡α=1(\vec{a} \times \vec{b}) \cdot (\vec{c} \times \vec{d}) = |\vec{a} \times \vec{b}|\,|\vec{c} \times \vec{d}|\cos\alpha = 1 ⇒∣a⃗×b⃗∣=1,∣c⃗×d⃗∣=1,cos⁡α=1\Rightarrow |\vec{a} \times \vec{b}| = 1,\quad |\vec{c} \times \vec{d}| = 1,\quad \cos\alpha = 1 a⃗×b⃗=c⃗×d⃗=n^\vec{a} \times \vec{b} = \vec{c} \times \vec{d} = \hat{n} ∣a⃗×b⃗∣=1⇒a⃗⋅b⃗=0|\vec{a} \times \vec{b}| = 1 \Rightarrow \vec{a} \cdot \vec{b} = 0 ∣c⃗×d⃗∣=1⇒c⃗⋅d⃗=0|\vec{c} \times \vec{d}| = 1 \Rightarrow \vec{c} \cdot \vec{d} = 0 a⃗,b⃗⊥n^andc⃗,d⃗⊥n^\vec{a},\vec{b} \perp \hat{n} \quad \text{and} \quad \vec{c},\vec{d} \perp \hat{n} ∴a⃗,b⃗,c⃗,d⃗ lie in the plane ⊥n^\therefore \vec{a},\vec{b},\vec{c},\vec{d} \text{ lie in the plane } \perp \hat{n} ∴a⃗,b⃗,c⃗ coplanar and b⃗,c⃗,d⃗ coplanar\therefore \vec{a},\vec{b},\vec{c} \text{ coplanar and } \vec{b},\vec{c},\vec{d} \text{ coplanar} ⇒(1), (2) are false\Rightarrow (1),\ (2) \text{ are false} n^×a⃗=(a⃗×b⃗)×a⃗=b⃗\hat{n} \times \vec{a} = (\vec{a} \times \vec{b}) \times \vec{a} = \vec{b} n^×c⃗=d⃗\hat{n} \times \vec{c} = \vec{d} If b⃗∥d⃗⇒n^×a⃗∥n^×c⃗\text{If } \vec{b} \parallel \vec{d} \Rightarrow \hat{n} \times \vec{a} \parallel \hat{n} \times \vec{c} ⇒a⃗∥c⃗⇒a⃗⋅c⃗=±1\Rightarrow \vec{a} \parallel \vec{c} \Rightarrow \vec{a} \cdot \vec{c} = \pm 1 But a⃗⋅c⃗=12  ✗\text{But } \vec{a} \cdot \vec{c} = \dfrac{1}{2} \ \ ✗ ∴b⃗,d⃗ are non-parallel⇒(3) is true\therefore \vec{b}, \vec{d} \text{ are non-parallel} \Rightarrow (3) \text{ is true} b⃗∥c⃗⇒a⃗⋅c⃗=±a⃗⋅b⃗=0\vec{b} \parallel \vec{c} \Rightarrow \vec{a} \cdot \vec{c} = \pm \vec{a} \cdot \vec{b} = 0 But a⃗⋅c⃗=12⇒(4) is false\text{But } \vec{a} \cdot \vec{c} = \dfrac{1}{2} \Rightarrow (4) \text{ is false} (3) b⃗,d⃗ are non-parallel\boxed{(3)\ \vec{b}, \vec{d} \text{ are non-parallel}}

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