If a⃗ and b⃗ are vectors such that |a⃗+b⃗|=√29 and a⃗×(2î+3ĵ+4k̂)=(2î+3ĵ+4k̂)×b⃗, then a possible value of (a⃗+b⃗)·(-7î+2ĵ+3k̂) is
a+b=29
a×c=c×b,c=2i^+3j^+4k^
Find a possible value of (a+b)⋅(−7i^+2j^+3k^)
1. (a+b)×c=0⇒(a+b)∥c
2. ∣a+b∣=∣c∣⇒a+b=±c
3. evaluate c⋅(−7i^+2j^+3k^)
a×c=c×b=−b×c
⇒ a×c+b×c=(a+b)×c=0
a+b∥c
∣c∣=4+9+16=29=∣a+b∣⇒a+b=±c
c⋅w=2(−7)+3(2)+4(3)=−14+6+12=4
(a+b)⋅w=±(c⋅w)=±4
4⇒option (3)