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JEE Advanced 2018 · Mechanical Properties of Fluids

A uniform capillary tube of inner radius rr is dipped vertically into a beaker filled with water. The water rises to a height hh in the capillary tube above the water surface in the beaker. The surface tension of water is σ\sigma. The angle of contact between water and the wall of the capillary tube is θ\theta. Ignore the mass of water in the meniscus. Which of the following statements is (are) true?

Answers: A. For a given material of the capillary tube, hh decreases with increase in rr · C. If this experiment is performed in a lift going up with a constant acceleration, then hh decreases

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Written solution

Step 1: Balance the forces acting on the water column.

The upward force due to surface tension is balanced by the weight of the water column.

Fup=2πrσcos⁡θF_{\text{up}} = 2\pi r \sigma \cos\theta W=ρ(πr2h)gW = \rho (\pi r^2 h) g

Equating the upward force and the weight yields the expression for the height hh:

2πrσcos⁡θ=ρπr2hg2\pi r \sigma \cos\theta = \rho \pi r^2 h g h=2σcos⁡θρgrh = \frac{2\sigma\cos\theta}{\rho g r}

Step 2: Analyze Statement (1) regarding the inner radius rr.

The height hh is inversely proportional to the inner radius rr.

h∝1rh \propto \frac{1}{r}

As rr increases, hh decreases. Therefore, Statement (1) is true.

Step 3: Analyze Statement (2) regarding the surface tension σ\sigma.

The height hh is directly proportional to the surface tension σ\sigma.

h∝σh \propto \sigma

Therefore, hh is not independent of σ\sigma. Thus, Statement (2) is false.

Step 4: Analyze Statement (3) regarding upward acceleration.

In a lift accelerating upwards with acceleration aa, the effective acceleration due to gravity increases.

geff=g+ag_{\text{eff}} = g + a h=2σcos⁡θρ(g+a)rh = \frac{2\sigma\cos\theta}{\rho (g+a) r}

Since geff>gg_{\text{eff}} > g, the height hh decreases. Therefore, Statement (3) is true.

Step 5: Analyze Statement (4) regarding the contact angle θ\theta.

The height hh is proportional to cos⁡θ\cos\theta, not directly to θ\theta.

h∝cos⁡θh \propto \cos\theta

Therefore, Statement (4) is false.

Answer: Statements (1) and (3) are true.

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