f′(x)=b2+x2f(x),f(0)=1,b=0
To find: which of statements (1)–(4) are True
fdf=b2+x2dx
lnf=b1tan−1(bx)+C
x=0, f=1: 0=0+C⇒C=0
f(x)=eb1tan−1(x/b)
f>0, b2+x2>0⇒f′(x)=b2+x2f(x)>0
⇒(1) is True
f′>0 even when b<0⇒(2) is False
g(x)=b1tan−1(bx) is odd⇒f(−x)=e−g(x)=f(x)1
⇒f(x)f(−x)=1⇒(3) is True
f(x)−f(−x)=eg(x)−e−g(x)=2sinh(g(x))=0
⇒(4) is False
True statements: (1), (3)
Answer: (1), (3)