arthham

JEE Advanced 2009 · Continuity and Differentiability

If the function f(x)=x3+ex2f(x)=x^{3}+e^{\frac{x}{2}} and g(x)=f−1(x)g(x)=f^{-1}(x), then the value of g′(1)g'(1) is ______.

Answer: 22

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If the function f(x)=x³+e^(x/2) and g(x)=f⁻¹(x), then the value of g'(1) is ______. f(x)=x3+ex/2f(x) = x^3 + e^{x/2} g(x)=f−1(x)g(x) = f^{-1}(x) To find: g′(1)\text{To find: } g'(1) g′(x)=1f′(g(x))g'(x) = \dfrac{1}{f'(g(x))} f(g(1))=1,f(0)=0+e0=1f(g(1)) = 1, \quad f(0) = 0 + e^{0} = 1 ⇒g(1)=0\Rightarrow g(1) = 0 f′(x)=3x2+12ex/2f'(x) = 3x^2 + \dfrac{1}{2}e^{x/2} f′(0)=0+12=12f'(0) = 0 + \dfrac{1}{2} = \dfrac{1}{2} g′(1)=1f′(g(1))=1f′(0)=11/2=2g'(1) = \dfrac{1}{f'(g(1))} = \dfrac{1}{f'(0)} = \dfrac{1}{1/2} = 2 g′(1)=2\boxed{g'(1) = 2}

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