JEE Advanced 2014 · Continuity and Differentiability
Let f:R→R and g:R→R be respectively given by f(x)=∣x∣+1 and g(x)=x2+1. Define h:R→R by h(x)=max{f(x),g(x)} if x≤0, and h(x)=min{f(x),g(x)} if x>0. The number of points at which h(x) is not differentiable is ____.
Let f:R → R and g:R → R be respectively given by f(x)=|x|+1 and g(x)=x²+1. Define h:R → R by h(x)= max{f(x),g(x)} if x ≤ 0,
min{f(x),g(x)} if x > 0. The number of points at which h(x) is not differentiable is ______.
f(x)=∣x∣+1,g(x)=x2+1h(x)={max(f,g),min(f,g),x≤0x>0Find: number of points where h is not differentiablef(x)=g(x)⇒∣x∣=x2⇒x=−1,0,1g−f=x2−∣x∣={x(x+1),x(x−1),x≤0x≥0h(x)=⎩⎨⎧x2+1,1−x,x2+1,x+1,x≤−1−1≤x≤00<x≤1x≥1h is smooth inside each piece; check the junctions x=−1,0,1x=−1:h−′(−1)=2x−1=−2,h+′(−1)=−1−2=−1⇒not differentiablex=0:h−′(0)=−1,h+′(0)=2x0=0−1=0⇒not differentiablex=1:h−′(1)=2x1=2,h+′(1)=12=1⇒not differentiableh not differentiable at x=−1,0,1⇒number=3