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JEE Advanced 2016 · Continuity and Differentiability

Let f:[−12,2]→Rf: \left[-\frac{1}{2}, 2\right] \to \mathbb{R} and g:[−12,2]→Rg: \left[-\frac{1}{2}, 2\right] \to \mathbb{R} be functions defined by f(x)=[x2−3]f(x) = [x^{2}-3] and g(x)=∣x∣f(x)+∣4x−7∣f(x)g(x) = |x| f(x) + |4x-7| f(x), where [y][y] denotes the greatest integer less than or equal to yy for y∈Ry \in \mathbb{R}. Then

Answers: B. ff is discontinuous exactly at four points in [−12,2]\left[-\frac{1}{2}, 2\right] · C. gg is NOT differentiable exactly at four points in (−12,2)\left(-\frac{1}{2}, 2\right)

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Given: f(x)=⌊x2−3⌋,g(x)=(∣x∣+∣4x−7∣)f(x)\text{Given: } f(x) = \lfloor x^2 - 3 \rfloor,\quad g(x) = \big(|x| + |4x-7|\big) f(x) domain [−12,2];[y]=⌊y⌋\text{domain } \left[-\dfrac{1}{2}, 2\right];\quad [y] = \lfloor y \rfloor To find: which of (1)–(4) are TRUE\text{To find: which of (1)--(4) are TRUE} 1. discontinuities of f (floor jumps)1.\ \text{discontinuities of } f \text{ (floor jumps)} 2. g=h f with h=∣x∣+∣4x−7∣2.\ g = h\,f \text{ with } h = |x| + |4x-7| 3. non-differentiability points of g3.\ \text{non-differentiability points of } g f(x)=⌊x2−3⌋ jumps where x2−3 crosses an integerf(x) = \lfloor x^2 - 3 \rfloor \text{ jumps where } x^2 - 3 \text{ crosses an integer} x∈[−12,2]⇒x2∈[0,4]⇒x2−3∈[−3,1]x \in \left[-\dfrac{1}{2}, 2\right] \Rightarrow x^2 \in [0,4] \Rightarrow x^2 - 3 \in [-3, 1] x2=1,2,3,4⇒x=1,2,3,2x^2 = 1, 2, 3, 4 \Rightarrow x = 1, \sqrt{2}, \sqrt{3}, 2 at x=0: x2−3 has a minimum, no integer crossing\text{at } x = 0:\ x^2 - 3 \text{ has a minimum, no integer crossing} f discontinuous at x=1,2,3,2⇒(2) TRUE, (1) FALSEf \text{ discontinuous at } x = 1, \sqrt2, \sqrt3, 2 \Rightarrow \text{(2) TRUE},\ \text{(1) FALSE} g(x)=h(x) f(x),h(x)=∣x∣+∣4x−7∣g(x) = h(x)\,f(x), \qquad h(x) = |x| + |4x-7| h(x)=∣x∣+∣4x−7∣>0 for all xh(x) = |x| + |4x-7| > 0 \text{ for all } x kinks of h:x=0andx=74=1.75\text{kinks of } h:\quad x = 0 \quad \text{and} \quad x = \dfrac{7}{4} = 1.75 at x=1,2,3: h≠0⇒g not differentiable (3 points)\text{at } x = 1, \sqrt2, \sqrt3:\ h \neq 0 \Rightarrow g \text{ not differentiable } (3 \text{ points}) x=74: 3<74<2⇒f(x)=⌊x2−3⌋=0x = \tfrac{7}{4}:\ \sqrt3 < \tfrac74 < 2 \Rightarrow f(x) = \lfloor x^2-3 \rfloor = 0 ⇒g≡0 near 74⇒g IS differentiable there\Rightarrow g \equiv 0 \text{ near } \tfrac74 \Rightarrow g \text{ IS differentiable there} x=0: f(0)=−3≠0 with ∣x∣ kink⇒g not differentiablex = 0:\ f(0) = -3 \neq 0 \text{ with } |x| \text{ kink} \Rightarrow g \text{ not differentiable} g not differentiable at 0,1,2,3⇒4 points⇒(3) TRUE, (4) FALSEg \text{ not differentiable at } 0, 1, \sqrt2, \sqrt3 \Rightarrow 4 \text{ points} \Rightarrow \text{(3) TRUE},\ \text{(4) FALSE} Answer: (2) and (3)\boxed{\text{Answer: (2) and (3)}}

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