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JEE Advanced 2016 · Trigonometric Functions

The number of values of θ\theta in the interval, (−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right) such that θ≠nπ5\theta \neq \frac{n\pi}{5} for n=0,±1,±2n = 0, \pm 1, \pm 2 and tan⁡θ=cot⁡5θ\tan \theta = \cot 5\theta as well as sin⁡2θ=cos⁡4θ\sin 2\theta = \cos 4\theta is

Answer: 33

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θ∈(−π2,π2)\theta \in \left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right) θ≠nπ5,n=0,±1,±2\theta \neq \dfrac{n\pi}{5}, \quad n = 0, \pm 1, \pm 2 tan⁡θ=cot⁡5θ\tan\theta = \cot 5\theta sin⁡2θ=cos⁡4θ\sin 2\theta = \cos 4\theta To find: the number of such θ\text{To find: the number of such } \theta 1. Solve tan⁡θ=cot⁡5θ\text{1. Solve } \tan\theta = \cot 5\theta 2. Solve sin⁡2θ=cos⁡4θ\text{2. Solve } \sin 2\theta = \cos 4\theta 3. Take common values, drop θ=nπ5\text{3. Take common values, drop } \theta = \dfrac{n\pi}{5} cot⁡A=tan⁡ ⁣(π2−A)\cot A = \tan\!\left(\dfrac{\pi}{2} - A\right) cot⁡5θ=tan⁡ ⁣(π2−5θ)\cot 5\theta = \tan\!\left(\dfrac{\pi}{2} - 5\theta\right) tan⁡θ=tan⁡ ⁣(π2−5θ)\tan\theta = \tan\!\left(\dfrac{\pi}{2} - 5\theta\right) θ=π2−5θ+kπ\theta = \dfrac{\pi}{2} - 5\theta + k\pi 6θ=π2+kπ6\theta = \dfrac{\pi}{2} + k\pi θ=π12+kπ6\theta = \dfrac{\pi}{12} + \dfrac{k\pi}{6} k=0: π12;k=1: π4;k=2: 5π12k=0:\ \dfrac{\pi}{12};\quad k=1:\ \dfrac{\pi}{4};\quad k=2:\ \dfrac{5\pi}{12} k=−1: −π12;k=−2: −π4;k=−3: −5π12k=-1:\ -\dfrac{\pi}{12};\quad k=-2:\ -\dfrac{\pi}{4};\quad k=-3:\ -\dfrac{5\pi}{12} θ∈{±π12, ±π4, ±5π12}\theta \in \left\{\pm\dfrac{\pi}{12},\ \pm\dfrac{\pi}{4},\ \pm\dfrac{5\pi}{12}\right\} ⇒6 values from the first equation\Rightarrow 6 \text{ values from the first equation} \cos 2x = 1 - 2\sin^2 x \cos 4\theta = 1 - 2\sin^2 2\theta \sin 2\theta = 1 - 2\sin^2 2\theta 2\sin^2 2\theta + \sin 2\theta - 1 = 0 2s^2 + s - 1 = 0,\quad s = \sin 2\theta 2s^2 + s - 1 = (2s - 1)(s + 1) = 0 \sin 2\theta = \dfrac{1}{2} \quad \text{or} \quad \sin 2\theta = -1 2\theta = \dfrac{\pi}{6} + 2k\pi \ \text{ or } \ \dfrac{5\pi}{6} + 2k\pi \theta = \dfrac{\pi}{12} + k\pi \ \text{ or } \ \dfrac{5\pi}{12} + k\pi \theta = \dfrac{\pi}{12},\ \dfrac{5\pi}{12} 2\theta = -\dfrac{\pi}{2} + 2k\pi \theta = -\dfrac{\pi}{4} + k\pi \ \Rightarrow\ \theta = -\dfrac{\pi}{4} \sin 2\theta = \cos 4\theta \Rightarrow \theta = -\dfrac{\pi}{4},\ \dfrac{\pi}{12},\ \dfrac{5\pi}{12} \text{Common: } \theta = -\dfrac{\pi}{4},\ \dfrac{\pi}{12},\ \dfrac{5\pi}{12} \text{Excluded: } \theta = 0,\ \pm\dfrac{\pi}{5},\ \pm\dfrac{2\pi}{5} -\dfrac{\pi}{4},\ \dfrac{\pi}{12},\ \dfrac{5\pi}{12} \ \notin\ \left{0,\ \pm\dfrac{\pi}{5},\ \pm\dfrac{2\pi}{5}\right} \text{Number of values of } \theta = 3$

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