arthham

JEE Advanced 2017 · Work, Energy and Power

A flat plate is moving normal to its plane through a gas under the action of a constant force FF. The gas is kept at a very low pressure. The speed of the plate vv is much less than the average speed uu of the gas molecules. Which of the following options is/are true?

Answers: A. The pressure difference between the leading and trailing faces of the plate is proportional to uvuv · B. The resistive force experienced by the plate is proportional to vv · D. At a later time the external force FF balances the resistive force

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Written solution

Step 1: Analyze the pressure on the leading and trailing faces.

In the reference frame of the plate, the gas molecules strike the leading face with a relative speed proportional to u+vu + v, and the trailing face with a relative speed proportional to u−vu - v.

Plead∝(u+v)2P_{\text{lead}} \propto (u+v)^2 Ptrail∝(u−v)2P_{\text{trail}} \propto (u-v)^2

Step 2: Calculate the pressure difference.

Subtract the pressure on the trailing face from the pressure on the leading face.

ΔP∝(u+v)2−(u−v)2\Delta P \propto (u+v)^2 - (u-v)^2 ΔP∝4uv\Delta P \propto 4uv ΔP∝uv\Delta P \propto uv

This shows the pressure difference is proportional to uvuv, making Option (1) true.

Step 3: Determine the resistive force on the plate.

The resistive force RR is the product of the pressure difference and the plate area AA.

R=ΔP⋅AR = \Delta P \cdot A

Since uu and AA are constants, we obtain the relation for the resistive force.

R∝vR \propto v

This shows the resistive force is proportional to vv, making Option (2) true.

Step 4: Analyze the acceleration of the plate.

Apply Newton's second law to write the equation of motion, where β\beta is a constant of proportionality.

mdvdt=F−βvm\frac{dv}{dt} = F - \beta v

Solving this differential equation with v(0)=0v(0) = 0 yields the velocity as a function of time.

v(t)=Fβ(1−e−βt/m)v(t) = \frac{F}{\beta}\left(1 - e^{-\beta t/m}\right)

Since the acceleration decreases exponentially over time, Option (3) is false.

Step 5: Evaluate the terminal state of the plate.

As t→∞t \to \infty, the velocity approaches a constant terminal value.

v→Fβv \to \frac{F}{\beta}

At this terminal speed, the net force becomes zero.

F=βv=RF = \beta v = R

Thus, the external force FF eventually balances the resistive force, making Option (4) is true.

Answer: The true options are (1), (2), and (4).

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