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JEE Advanced 2019 · Continuity and Differentiability

For a polynomial g(x)g(x) with real coefficients, let mgm_g denote the number of distinct real roots of g(x)g(x). Suppose SS is the set of polynomials with real coefficients defined by S={(x2−1)2(a0+a1x+a2x2+a3x3):a0,a1,a2,a3∈R}S = \{(x^{2} - 1)^{2}(a_0 + a_1 x + a_2 x^{2} + a_3 x^{3}) : a_0, a_1, a_2, a_3 \in \mathbb{R}\}. For a polynomial ff, let f′f' and f′′f'' denote its first and second order derivatives, respectively. Then the minimum possible value of (mf′+mf′′)(m_{f'} + m_{f''}), where f∈Sf \in S, is ______

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Written solution

f(x)=(x2−1)2 p(x),p(x)=a0+a1x+a2x2+a3x3f(x) = (x^2 - 1)^2\,p(x),\quad p(x) = a_0 + a_1 x + a_2 x^2 + a_3 x^3

f(±1)=0 and f′(±1)=0 ⇒ ±1 are double roots of ff(\pm 1) = 0 \text{ and } f'(\pm 1) = 0 \ \Rightarrow\ \pm 1 \text{ are double roots of } f

To find: min⁡f∈S (mf′+mf′′)\text{To find: } \min_{f\in S}\,(m_{f'} + m_{f''})

f(±1)=0,f′(±1)=0f(\pm1)=0,\quad f'(\pm1)=0

Rolle: ∃ c∈(−1,1) with f′(c)=0\text{Rolle: } \exists\, c\in(-1,1)\ \text{with}\ f'(c)=0

mf′≥3(−1, c, 1)m_{f'} \ge 3 \qquad (-1,\ c,\ 1)

Rolle on f′: ∃ d1∈(−1,c), d2∈(c,1): f′′(d1)=f′′(d2)=0\text{Rolle on } f':\ \exists\, d_1\in(-1,c),\ d_2\in(c,1):\ f''(d_1)=f''(d_2)=0

mf′′≥2m_{f''} \ge 2

mf′+mf′′≥3+2=5m_{f'} + m_{f''} \ge 3 + 2 = 5

f=(x2−1)2:f′=4x(x2−1) ⇒ roots −1, 0, 1  (3)f = (x^2-1)^2:\quad f' = 4x(x^2-1)\ \Rightarrow\ \text{roots } -1,\ 0,\ 1\ \ (3)

f′′=4(3x2−1) ⇒ roots ±13  (2)f'' = 4(3x^2-1)\ \Rightarrow\ \text{roots } \pm\tfrac{1}{\sqrt3}\ \ (2)

min⁡ (mf′+mf′′)=5\min\,(m_{f'} + m_{f''}) = 5

5\boxed{5}

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