Given: f(x)=sin(πcosx),g(x)=cos(2πsinx)
X={x:f(x)=0},Y={x:f′(x)=0}
Z={x:g(x)=0},W={x:g′(x)=0}
To find: the matching of X,Y,Z,W
with the correct statements from Column II (p)–(u)
1. find zeros of f, f′, g, g′
2. write each set and check AP
3. check membership and match options
f(x)=0⇒sin(πcosx)=0⇒πcosx=nπ
⇒cosx=n, n∈Z;cosx∈[−1,1]⇒n=−1,0,1
X={x:cosx∈{−1,0,1}}={2mπ:m≥1}
X={2π,π,23π,2π,25π,…}
successive gaps=2π⇒X is an AP⇒(q)
2π, 23π, 4π, 7π∈X⇒X⊇(p)
f′(x)=−πsinxcos(πcosx)
f′(x)=0⇒sinx=0 or cos(πcosx)=0
sinx=0⇒x=nπ
cos(πcosx)=0⇒πcosx=2π+nπ
⇒cosx=21+n⇒cosx=±21
⇒x=±3π+2kπ, ±32π+2kπ
Y={3mπ:m≥1}={3π,32π,π,34π,35π,…}
common difference=3π⇒Y is an AP⇒(q)
3π,32π,π∈Y⇒Y⊇(t)
g(x)=0⇒cos(2πsinx)=0⇒2πsinx=2π+nπ
⇒sinx=41+2n=±41, ±43
Z={x:sinx∈{±41,±43}}
gaps between consecutive Z-elements are not equal
⇒Z is NOT an AP⇒(r)
sin2π=1⇒2π∈/Z
sin6π=21⇒6π∈/Z
Z matches only (r)
g′(x)=−2πcosxsin(2πsinx)
g′(x)=0⇒cosx=0 or sin(2πsinx)=0
cosx=0⇒x=2(2k+1)π
sin(2πsinx)=0⇒sinx=2n=0, ±21, ±1
⇒x=nπ, 6π+2kπ, 65π+2kπ, …
W={2mπ}∪{6π+2kπ, 65π+2kπ, 67π+2kπ, 611π+2kπ}
gaps of W alternate 3π,6π⇒NOT an AP⇒(r)
2π, 23π, 4π, 7π∈W⇒W⊇(p)
6π, 67π, 613π∈W⇒W⊇(s)
X→(p),(q);Y→(q),(t)
Z→(r);W→(p),(r),(s)
(1) (IV)=W: (p),(r),(s) ✓
(2), (3) claim Z is AP / contains (u) ×
(4) claims W is AP / contains (t) ×
X→(p,q); Y→(q,t); Z→(r); W→(p,r,s)
correct option (1)