M = 2 -1
1 0
M²⁶ = p q
r s , ∑ₖ₌₁²⁶ Mᵏ = a b
c d
To find: which of statements (1)–(4) are TRUE
det(M−λI)=λ2−2λ+1=(λ−1)2
M - I = 1 -1
1 -1 , (M-I)² = 0
M=I+N,N=M−I,N2=0
Mk=(I+N)k=I+kN
M²⁶ = I+26N = 27 -26
26 -25
p=27, q=−26, r=26, s=−25
J₂(1) = 1 1
0 1 , M ∼ J₂(1)
⇒(1) is TRUE
∑k=126Mk=26I+226⋅27N=26I+351N
= 377 -351
351 -325
a=377=378⇒(2) is FALSE
detM=1⇒det(M26)=1 (unimodular)
⇒unique integer solution⇒(3) is TRUE
a+t b
c d+t = 26I + 351N + tI
eigenvalue 26+t>0⇒det=0⇒(4) is TRUE
TRUE statements: (1), (3), (4)
Answer: (1), (3), (4)