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JEE Advanced 2026 · Determinants

Consider the matrix M=[2−110]M = \begin{bmatrix} 2 & -1 \\ 1 & 0 \end{bmatrix} Let pp, qq, rr, ss, aa, bb, cc and dd be integers such that M26=[pqrs]M^{26} = \begin{bmatrix} p & q \\ r & s \end{bmatrix} and ∑k=126Mk=[abcd]\sum_{k=1}^{26} M^{k} = \begin{bmatrix} a & b \\ c & d \end{bmatrix} Then which of the following statements is (are) TRUE?

Answers: A. There exists a 2×22 \times 2 invertible matrix NN with real entries such that MN=N[1101]MN = N\begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix} · C. For any two given integers mm and nn, there exist unique integers xx and yy such that px+qy=mpx + qy = m and rx+sy=nrx + sy = n · D. For each positive real number tt, the system of linear equations (a+t)x+by=1(a + t)x + by = 1, cx+(d+t)y=−1cx + (d + t)y = -1 has a unique solution

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Written solution

M = 2 -1 1 0 M²⁶ = p q r s , ∑ₖ₌₁²⁶ Mᵏ = a b c d

To find: which of statements (1)–(4) are TRUE\text{To find: which of statements (1)--(4) are TRUE}

det⁡(M−λI)=λ2−2λ+1=(λ−1)2\det(M-\lambda I) = \lambda^2 - 2\lambda + 1 = (\lambda-1)^2

M - I = 1 -1 1 -1 , (M-I)² = 0

M=I+N,N=M−I,N2=0M = I + N, \quad N = M-I, \quad N^2 = 0

Mk=(I+N)k=I+kNM^k = (I+N)^k = I + kN

M²⁶ = I+26N = 27 -26 26 -25

p=27, q=−26, r=26, s=−25p=27,\ q=-26,\ r=26,\ s=-25

J₂(1) = 1 1 0 1 , M ∼ J₂(1)

⇒(1) is TRUE\Rightarrow (1) \text{ is TRUE}

∑k=126Mk=26I+26⋅272N=26I+351N\sum_{k=1}^{26} M^k = 26I + \dfrac{26\cdot 27}{2}N = 26I + 351N

= 377 -351 351 -325

a=377≠378  ⇒  (2) is FALSEa=377 \neq 378 \;\Rightarrow\; (2) \text{ is FALSE}

det⁡M=1  ⇒  det⁡(M26)=1 (unimodular)\det M = 1 \;\Rightarrow\; \det(M^{26}) = 1 \ (\text{unimodular})

⇒unique integer solution  ⇒  (3) is TRUE\Rightarrow \text{unique integer solution} \;\Rightarrow\; (3) \text{ is TRUE}

a+t b c d+t = 26I + 351N + tI

eigenvalue 26+t>0  ⇒  det⁡≠0  ⇒  (4) is TRUE\text{eigenvalue } 26+t > 0 \;\Rightarrow\; \det \neq 0 \;\Rightarrow\; (4) \text{ is TRUE}

TRUE statements: (1), (3), (4)\boxed{\text{TRUE statements: (1), (3), (4)}}

Answer: (1), (3), (4)\text{Answer: (1), (3), (4)}

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