Two small particles of equal masses start moving in opposite directions from a point in a horizontal circular orbit. Their tangential velocities are and , respectively, as shown in the figure. Between collisions, the particles move with constant speeds. After making how many elastic collisions, other than that at , these two particles will again reach the point ?
Answer: C.
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Written solution
Step 1: Analyze the collision dynamics.
For two particles of equal mass undergoing a head-on elastic collision, they exchange their velocities. This velocity exchange is mathematically equivalent to a "pass-through" scenario, where the two particles continue along their paths with their original speeds as if they passed through each other.
Step 2: Calculate the time and position of the first collision.
Let the radius of the circular orbit be . The total circumference of the orbit is . Since the particles move in opposite directions with speeds and , their relative speed is:
The time taken for the first collision to occur is:
The angular position of the first collision from point is determined by the distance traveled by the slower particle:
Step 3: Determine the positions of subsequent collisions.
Using the pass-through equivalence, subsequent collisions occur at regular intervals of .
The second collision occurs at time :
The angular position of the second collision is:
The third meeting occurs at time :
The angular position of the third meeting is:
This third meeting occurs exactly at the starting point .
Step 4: Count the collisions between point .
The particles collide at and before meeting again at point (). Thus, there are exactly elastic collisions between their departure from and their return to .
Answer: 2