arthham

JEE Advanced 2009 · Work, Energy and Power

Two small particles of equal masses start moving in opposite directions from a point AA in a horizontal circular orbit. Their tangential velocities are vv and 2v2v, respectively, as shown in the figure. Between collisions, the particles move with constant speeds. After making how many elastic collisions, other than that at AA, these two particles will again reach the point AA?

Answer: C. 22

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Written solution

Step 1: Analyze the collision dynamics.

For two particles of equal mass undergoing a head-on elastic collision, they exchange their velocities. This velocity exchange is mathematically equivalent to a "pass-through" scenario, where the two particles continue along their paths with their original speeds as if they passed through each other.

Step 2: Calculate the time and position of the first collision.

Let the radius of the circular orbit be RR. The total circumference of the orbit is 2πR2\pi R. Since the particles move in opposite directions with speeds vv and 2v2v, their relative speed is:

vrel=v+2v=3vv_{\text{rel}} = v + 2v = 3v

The time t1t_1 taken for the first collision to occur is:

t1=2πR3vt_1 = \frac{2\pi R}{3v}

The angular position θ1\theta_1 of the first collision from point AA is determined by the distance traveled by the slower particle:

θ1=v⋅t1R=2π3=120∘\theta_1 = \frac{v \cdot t_1}{R} = \frac{2\pi}{3} = 120^\circ

Step 3: Determine the positions of subsequent collisions.

Using the pass-through equivalence, subsequent collisions occur at regular intervals of Δt=t1\Delta t = t_1.

The second collision occurs at time t2t_2:

t2=2t1=4πR3vt_2 = 2t_1 = \frac{4\pi R}{3v}

The angular position of the second collision is:

θ2=4π3=240∘\theta_2 = \frac{4\pi}{3} = 240^\circ

The third meeting occurs at time t3t_3:

t3=3t1=2πRvt_3 = 3t_1 = \frac{2\pi R}{v}

The angular position of the third meeting is:

θ3=2π≡0∘\theta_3 = 2\pi \equiv 0^\circ

This third meeting occurs exactly at the starting point AA.

Step 4: Count the collisions between point AA.

The particles collide at 120∘120^\circ and 240∘240^\circ before meeting again at point AA (360∘360^\circ). Thus, there are exactly 22 elastic collisions between their departure from AA and their return to AA.

Answer: 2

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