arthham

JEE Advanced 2012 · Matrices

If PP is a 3×33 \times 3 matrix such that PT=2P+IP^{T} = 2P + I, where PTP^{T} is the transpose of PP and II is the 3×33 \times 3 identity matrix, then there exists a column matrix X=[xyz]≠[000]X = \begin{bmatrix} x \\ y \\ z \end{bmatrix} \neq \begin{bmatrix} 0 \\ 0 \\ 0 \end{bmatrix} such that

Answer: D. PX=−XPX = -X

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Written solution

If P is a 3 × 3 matrix such that P^T = 2P + I, where P^T is the transpose of P and I is the 3 × 3 identity matrix, then there exists a column matrix X = x y z ≠ 0 0 0 such that

PT=2P+IP^{T}=2P+I

P: 3×3,I: 3×3 identityP:\ 3\times 3,\quad I:\ 3\times 3 \text{ identity}

Find X≠0 with PX=λX among λ∈{0,1,2,−1}\text{Find } X\neq 0 \text{ with } PX=\lambda X \text{ among } \lambda\in\{0,1,2,-1\}

Transpose both sides: (PT)T=(2P+I)T\text{Transpose both sides: } (P^{T})^{T}=(2P+I)^{T}

⇒P=2PT+I\Rightarrow P=2P^{T}+I

PT=2P+I⋯(1)P^{T}=2P+I \quad \cdots(1)

P=2PT+I⋯(2)P=2P^{T}+I \quad \cdots(2)

Substitute (1) in (2): P=2(2P+I)+I\text{Substitute (1) in (2): } P=2(2P+I)+I

P=4P+2I+I=4P+3IP=4P+2I+I=4P+3I

P=4P+3I⇒−3P=3IP=4P+3I \Rightarrow -3P=3I

⇒P=−I\Rightarrow P=-I

PT=(−I)T=−I,2P+I=2(−I)+I=−IP^{T}=(-I)^{T}=-I,\quad 2P+I=2(-I)+I=-I

⇒P=−I satisfies (1)\Rightarrow P=-I \text{ satisfies (1)}

PX=(−I)X=−Xfor every X≠0PX=(-I)X=-X \quad \text{for every } X\neq 0

⇒option (4)\Rightarrow \text{option } (4)

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