I₃ = 1 0 0
0 1 0
0 0 1
elementary ROW transformations only
To find: which option is reachable from I3 by row ops
row op⇔left-multiply by an invertible E
⇒ rank preserved, det=0 preserved
A reachable from I3⟺A invertible⟺detA=0
1. det of each option
2. pick the one with det=0
detA1=0(all three rows identical)
detA2=1(3−8)−1(2−4)+1(4−3)=−5+2+1=−2=0
A3: R3=3R2−4R1⇒detA3=0
A4: R3=R1+R2⇒detA4=0
only detA2=−2=0⇒A2 is reachable
option (2)