arthham

JEE Advanced 2013 · Work, Energy and Power

A particle of mass 0.2 kg is moving in one dimension under a force that delivers a constant power 0.5 W to the particle. If the initial speed (in ms−1)^{-1}) of the particle is zero, the speed (in ms−1)^{-1}) after 5 s is ____.

Answer: 55

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Written solution

Step 1: Identify the given parameters.

The given values for the particle are:

m=0.2 kgm = 0.2 \text{ kg} P=0.5 WP = 0.5 \text{ W} u=0 m s−1 at t=0u = 0 \text{ m s}^{-1} \text{ at } t = 0

Step 2: Relate power to kinetic energy.

Power is defined as the rate of change of kinetic energy.

P=dKdtP = \frac{dK}{dt} dK=P dtdK = P \, dt

Step 3: Integrate to find the kinetic energy at t=5 st = 5\text{ s}.

Integrating both sides from t=0t = 0 to t=5 st = 5\text{ s} yields:

K=∫05P dtK = \int_{0}^{5} P \, dt K=PtK = P t K=0.5×5=2.5 JK = 0.5 \times 5 = 2.5 \text{ J}

Step 4: Calculate the final speed of the particle.

Use the relation between kinetic energy and speed.

K=12mv2K = \frac{1}{2} m v^2 v=2Kmv = \sqrt{\frac{2K}{m}} v=2×2.50.2v = \sqrt{\frac{2 \times 2.5}{0.2}} v=25=5 m s−1v = \sqrt{25} = 5 \text{ m s}^{-1}

Answer: 5

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