arthham

JEE Advanced 2020 · System of Particles and Rotational Motion

A football of radius RR is kept on a hole of radius rr (r<R)(r < R) made on a plank kept horizontally. One end of the plank is now lifted so that it gets tilted making an angle θ\theta from the horizontal as shown in the figure below. The maximum value of θ\theta so that the football does not start rolling down the plank satisfies (figure is schematic and not drawn to scale)

Answer: A. sin⁡θ=rR\sin\theta = \frac{r}{R}

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Written solution

Step 1: Identify the geometry of the contact points.

The football of radius RR rests on a hole of radius rr in the plank, touching the two edges of the hole.

Let α\alpha be the angle that the line connecting the center of the ball to either contact edge makes with the normal to the plank.

sin⁡α=rR\sin\alpha = \frac{r}{R}

Step 2: Analyze the forces at the verge of rolling.

At the critical angle where the football is on the verge of rolling down, the normal force at the uphill edge becomes zero.

N1=0N_{1} = 0

Step 3: Apply the torque balance about the downhill edge.

For the ball to remain in equilibrium, the line connecting the center of the ball to the downhill contact edge must be vertical.

The normal to the plank makes an angle θ\theta with the vertical, and the line from the center of the ball to the downhill edge makes an angle α\alpha with the normal to the plank.

θ=α\theta = \alpha

Step 4: Relate the critical angle to the radii.

Substitute the relation for α\alpha into the equilibrium condition.

sin⁡θ=sin⁡α\sin\theta = \sin\alpha sin⁡θ=rR\sin\theta = \frac{r}{R}

Answer: The maximum value of θ\theta satisfies sin⁡θ=rR\sin\theta = \dfrac{r}{R}.

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