arthham

JEE Advanced 2021 · Conic Sections

Let EE denote the parabola y2=8xy^{2} = 8x. Let P=(−2,4)P = (-2, 4), and let QQ and Q′Q' be two distinct points on EE such that the lines PQPQ and PQ′PQ' are tangents to EE. Let FF be the focus of EE. Then which of the following statements is (are) TRUE? (1) The triangle PFQPFQ is a right-angled triangle (2) The triangle QPQ′QPQ' is a right-angled triangle (3) The distance between PP and FF is 525\sqrt{2} (4) FF lies on the line joining QQ and Q′Q'

Answers: A. The triangle PFQPFQ is a right-angled triangle · B. The triangle QPQ′QPQ' is a right-angled triangle · D. FF lies on the line joining QQ and Q′Q'

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Let E denote the parabola y² = 8x. Let P = (-2, 4), and let Q and Q' be two distinct points on E such that the lines PQ and PQ' are tangents to E. Let F be the focus of E. Then which of the following statements is (are) TRUE? Given: E: y2=8x\text{Given: } E:\ y^2 = 8x P(−2,4);PQ, PQ′ are tangents to EP(-2,4);\quad PQ,\ PQ' \text{ are tangents to } E F=the focus of EF = \text{the focus of } E To find: which of (1), (2), (3), (4) are TRUE\text{To find: which of } (1),\ (2),\ (3),\ (4) \text{ are TRUE} Plan: find F, tangents from P, then test each statement\text{Plan: find } F, \text{ tangents from } P, \text{ then test each statement} (1) PFQ(2) QPQ′(3) PF(4) F∈QQ′(1)\ PFQ\quad (2)\ QPQ'\quad (3)\ PF\quad (4)\ F \in QQ' y2=4ax⇒4a=8⇒a=2y^2 = 4ax \Rightarrow 4a = 8 \Rightarrow a = 2 F=(a,0)=(2,0)F = (a,0) = (2,0) Parabola y2=8x, focus F(2,0)\text{Parabola } y^2 = 8x,\ \text{focus } F(2,0) Tangent of slope m: y=mx+am=mx+2m\text{Tangent of slope } m:\ y = mx + \dfrac{a}{m} = mx + \dfrac{2}{m} At P(−2,4): 4=−2m+2m\text{At } P(-2,4):\ 4 = -2m + \dfrac{2}{m} m2+2m−1=0⇒m=−1±2m^2 + 2m - 1 = 0 \Rightarrow m = -1 \pm \sqrt{2} Contact:(am2,2am)=(2m2,4m)\text{Contact}: \left(\dfrac{a}{m^2}, \dfrac{2a}{m}\right) = \left(\dfrac{2}{m^2}, \dfrac{4}{m}\right) Q(6+42, 4+42)Q\left(6+4\sqrt{2},\ 4+4\sqrt{2}\right) Q′(6−42, 4−42)Q'\left(6-4\sqrt{2},\ 4-4\sqrt{2}\right) Tangents PQ and PQ′\text{Tangents } PQ \text{ and } PQ' FP→=(−4,4),FQ→=(4+42, 4+42)\overrightarrow{FP} = (-4,4),\quad \overrightarrow{FQ} = (4+4\sqrt{2},\ 4+4\sqrt{2}) FP→⋅FQ→=−4(4+42)+4(4+42)=0\overrightarrow{FP}\cdot\overrightarrow{FQ} = -4(4+4\sqrt{2}) + 4(4+4\sqrt{2}) = 0 ⇒∠PFQ=90∘⇒(1) TRUE\Rightarrow \angle PFQ = 90^\circ \Rightarrow (1)\ \text{TRUE} PQ→=4(2+2, 2),PQ′→=4(2−2, −2)\overrightarrow{PQ} = 4(2+\sqrt{2},\ \sqrt{2}),\quad \overrightarrow{PQ'} = 4(2-\sqrt{2},\ -\sqrt{2}) PQ→⋅PQ′→=16[(4−2)−2]=0\overrightarrow{PQ}\cdot\overrightarrow{PQ'} = 16\left[(4-2) - 2\right] = 0 ⇒∠QPQ′=90∘⇒(2) TRUE\Rightarrow \angle QPQ' = 90^\circ \Rightarrow (2)\ \text{TRUE} (3) PF=(2−(−2))2+(0−4)2=16+16(3)\ PF = \sqrt{(2-(-2))^2 + (0-4)^2} = \sqrt{16+16} =42≠52⇒(3) FALSE= 4\sqrt{2} \ne 5\sqrt{2} \Rightarrow (3)\ \text{FALSE} (4) Chord of contact QQ′: y=x−2(4)\ \text{Chord of contact } QQ':\ y = x - 2 F(2,0): 0=2−2 ✓⇒(4) TRUEF(2,0):\ 0 = 2 - 2\ \checkmark \Rightarrow (4)\ \text{TRUE} (1), (2), (4) are TRUE;(3) is FALSE(1),\ (2),\ (4)\ \text{are TRUE};\quad (3)\ \text{is FALSE} Answer: (1), (2), (4)\boxed{\text{Answer: } (1),\ (2),\ (4)}

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