Consider the hyperbola 100x2−64y2=1 with foci at S and S1, where S lies on the positive x-axis.
Let P be a point on the hyperbola, in the first quadrant.
Let ∠SPS1=α, with α<2π.
The straight line passing through the point S and having the same slope as that of the tangent at P to the hyperbola, intersects the straight line S1P at P1.
Let δ be the distance of P from the straight line SP1, and β=S1P.
Then the greatest integer less than or equal to 9βδsin2α is ______.
Consider the hyperbola x²/100 - y²/64 = 1 with foci at S and S₁, where S lies on the positive x-axis. Let P be a point on the hyperbola, in the first quadrant. Let ∠ SPS₁ = α, with α < π/2. The straight line passing through the point S and having the same slope as that of the tangent at P to the hyperbola, intersects the straight line S₁P at P₁. Let δ be the distance of P from the straight line SP₁, and β = S₁P. Then the greatest integer less tha
100x2−64y2=1:a=10,b=8,c=241S(241,0),S1(−241,0),P in first quadrant∠SPS1=α<2πLine through S with slope=tangent slope at Pmeets S1P at P1;δ=dist(P,SP1),β=S1PFind ⌊9βδsin2α⌋Plan: 1.draw hyperbola, foci2.tangent at P;line through S⇒P13.use PS1−PS=2a and law of cosines100x2−64y2=1,a=10,b=8c=a2+b2=164=241S(241,0),S1(−241,0)P on the hyperbola, first quadrant∠SPS1=α<2πTangent at P(x0,y0):100xx0−64yy0=1slope m=25y016x0through S with slope m:SP1∥tangent at PSP1∩S1P=P1tangent at P bisects ∠SPS1δ=dist(P,SP1)=PS⋅sin2αβ=S1Pd2−d1=2a=20,d1=SP,d2=S1PSS12=d12+d22−2d1d2cosα,SS1=2c4c2=(d2−d1)2+2d1d2(1−cosα)4c2=4a2+4d1d2sin22αd1d2sin22α=c2−a2=b2=64βδsin2α=d1d2sin22α=649βδsin2α=964≈7.11⌊9βδsin2α⌋=7