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JEE Advanced 2022 · Conic Sections

Consider the parabola y2=4xy^{2} = 4x. Let SS be the focus of the parabola. A pair of tangents drawn to the parabola from the point P=(−2,1)P = (-2, 1) meet the parabola at P1P_1 and P2P_2. Let Q1Q_1 and Q2Q_2 be points on the lines SP1SP_1 and SP2SP_2 respectively such that PQ1PQ_1 is perpendicular to SP1SP_1 and PQ2PQ_2 is perpendicular to SP2SP_2. Then, which of the following is/are TRUE?

Answers: A. SQ1=2SQ_1 = 2 · B. Q1Q2=3105Q_1Q_2 = \frac{3\sqrt{10}}{5} · C. PQ1=3PQ_1 = 3 · D. SQ2=1SQ_2 = 1

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Consider the parabola y² = 4x. Let S be the focus of the parabola. A pair of tangents drawn to the parabola from the point P = (-2, 1) meet the parabola at P₁ and P₂. Let Q₁ and Q₂ be points on the lines SP₁ and SP₂ respectively such that PQ₁ is perpendicular to SP₁ and PQ₂ is perpendicular to SP₂. Then, which of the following is/are TRUE? Given: parabola y2=4x, focus S\text{Given: parabola } y^2 = 4x,\ \text{focus } S P=(−2, 1)P = (-2,\ 1) Tangents from P touch at P1, P2\text{Tangents from } P \text{ touch at } P_1,\ P_2 PQ1⊥SP1,PQ2⊥SP2PQ_1 \perp SP_1,\quad PQ_2 \perp SP_2 Check which options are true\text{Check which options are true} y2=4x⇒a=1,S=(1,0)y^2 = 4x \Rightarrow a = 1,\quad S = (1,0) 1. slopes of tangents from P1.\ \text{slopes of tangents from } P 2. contact points P1, P22.\ \text{contact points } P_1,\ P_2 3. feet Q1, Q2⇒check options3.\ \text{feet } Q_1,\ Q_2 \Rightarrow \text{check options} y=mx+1my = mx + \frac{1}{m} 1=−2m+1m⇒2m2+m−1=01 = -2m + \frac{1}{m} \Rightarrow 2m^2 + m - 1 = 0 (2m−1)(m+1)=0⇒m=12, −1(2m-1)(m+1) = 0 \Rightarrow m = \frac{1}{2},\ -1 y=x2+2,y=−x−1y = \frac{x}{2} + 2,\qquad y = -x - 1 point (at2,2at); tangent slope=1t⇒t=1m\text{point } (at^2, 2at);\ \text{tangent slope} = \frac{1}{t} \Rightarrow t = \frac{1}{m} m=12⇒P1(4,4);m=−1⇒P2(1,−2)m=\frac{1}{2} \Rightarrow P_1(4,4);\quad m=-1 \Rightarrow P_2(1,-2) SP2: x=1⇒Q2=(1,1)SP_2:\ x = 1 \Rightarrow Q_2 = (1,1) SQ2=1⇒option (4) TRUESQ_2 = 1 \Rightarrow \text{option (4) TRUE} SP1: (1+3λ, 4λ)SP_1:\ (1+3\lambda,\ 4\lambda) (Q1−P)⋅(3,4)=0⇒5+25λ=0⇒λ=−15(Q_1-P)\cdot(3,4)=0 \Rightarrow 5 + 25\lambda = 0 \Rightarrow \lambda = -\frac{1}{5} Q1=(25, −45)Q_1 = \left(\frac{2}{5},\ -\frac{4}{5}\right) PQ1=(125)2+(95)2=155=3PQ_1 = \sqrt{\left(\frac{12}{5}\right)^2 + \left(\frac{9}{5}\right)^2} = \frac{15}{5} = 3 ⇒option (3) TRUE\Rightarrow \text{option (3) TRUE} SQ1=9+1625=1≠2SQ_1 = \sqrt{\frac{9+16}{25}} = 1 \neq 2 ⇒option (1) FALSE\Rightarrow \text{option (1) FALSE} Q1Q2=9+815=3105Q_1Q_2 = \frac{\sqrt{9+81}}{5} = \frac{3\sqrt{10}}{5} ⇒option (2) TRUE\Rightarrow \text{option (2) TRUE} True: (2), (3), (4)\text{True: (2)},\ (3),\ (4) Answer: (2), (3), (4)\boxed{\text{Answer: (2), (3), (4)}}

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