Let S = {a + b√2 : a, b ∈ Z}, T₁ = {(-1+√2)ⁿ : n ∈ N} and T₂ = {(1+√2)ⁿ : n ∈ N}. Then which of the following statements is (are) TRUE?
S={a+b2:a,b∈Z}T1={(−1+2)n:n∈N},T2={(1+2)n:n∈N}To find: which of (1), (2), (3), (4) are TRUE.Plan: verify (1), (2), (3), (4) one by one.Key: (−1+2)(1+2)=1(−1+2)(1+2)=−1+2=1⇒(−1+2)n=(1+2)−n(−1+2),(1+2)∈SS closed under ×⇒(−1+2)n,(1+2)n∈S(1)Z⊂S,T1⊂S,T2⊂S⇒Z∪T1∪T2⊂S✓tn=(2−1)n,0<2−1<1tn↓0 as n→∞(2−1)8≈8.66×10−4>20241(2−1)9≈3.59×10−4<20241(2−1)9∈T1∩(0,20241)(2)FALSE×un=(1+2)n,1+2>1un↑∞ as n→∞(1+2)8≈1154<2024(1+2)9≈2786>2024(1+2)9∈T2∩(2024,∞)=ϕ(3)TRUE✓cos(π(a+b2))+isin(π(a+b2))=eiπ(a+b2)=eiπa⋅eiπb2=(−1)a(cos(πb2)+isin(πb2))Real integer requires sin(πb2)=0⇒b2=k∈Z⇒b=0(2irrational)b=0⇒(−1)a∈Z(4)TRUE✓(1),(3),(4)are TRUE