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JEE Advanced 2007 · Complex Numbers and Quadratic Equations

A man walks a distance of 3 units from the origin towards the north-east (N 45∘45^\circ E) direction. From there, he walks a distance of 4 units towards the north-west (N 45∘45^\circ W) direction to reach a point P. Then the position of P in the Argand plane is

Answer: D. (3+4i)eiπ/4(3 + 4i)e^{i\pi/4}

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Written solution

First: 3 units from O along N 45∘E\text{First: } 3 \text{ units from } O \text{ along } N\,45^\circ E

then: 4 units along N 45∘W to reach P\text{then: } 4 \text{ units along } N\,45^\circ W \text{ to reach } P

To find: position of P in the Argand plane\text{To find: position of } P \text{ in the Argand plane}

1. write the two displacements as complex numbers1.\ \text{write the two displacements as complex numbers} 2. add them2.\ \text{add them} 3. match with the options3.\ \text{match with the options} N 45∘E⇒45∘ from the positive real axisN\,45^\circ E \Rightarrow 45^\circ \text{ from the positive real axis} z1=3eiπ/4z_1 = 3e^{i\pi/4} z1=3(cos⁡45∘+isin⁡45∘)z_1 = 3(\cos45^\circ + i\sin45^\circ) =32+i 32= \dfrac{3}{\sqrt2} + i\,\dfrac{3}{\sqrt2} N 45∘W⇒135∘ from the positive real axisN\,45^\circ W \Rightarrow 135^\circ \text{ from the positive real axis} z2=4ei3π/4z_2 = 4e^{i3\pi/4} ei3π/4=eiπ/2⋅eiπ/4e^{i3\pi/4}=e^{i\pi/2}\cdot e^{i\pi/4} =i eiπ/4= i\,e^{i\pi/4} z2=4i eiπ/4z_2 = 4i\,e^{i\pi/4} P=z1+z2=3eiπ/4+4i eiπ/4P = z_1 + z_2 = 3e^{i\pi/4} + 4i\,e^{i\pi/4} P=(3+4i) eiπ/4P = (3+4i)\,e^{i\pi/4} P=(3+4i) eiπ/4P = (3+4i)\,e^{i\pi/4} Answer: option (4)\text{Answer: option (4)}

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