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JEE Advanced 2009 · Probability (Class 12)

An experiment has 10 equally likely outcomes. Let AA and BB be non-empty events of the experiment. If AA consists of 4 outcomes, the number of outcomes that BB must have so that AA and BB are independent, is

Answer: D. 55 or 1010

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Written solution

Given: n(S)=10 equally likely outcomes\text{Given: } n(S) = 10 \text{ equally likely outcomes}

n(A)=4,A,B≠∅n(A) = 4, \qquad A,B \neq \varnothing

Find n(B) such that A and B are independent\text{Find } n(B) \text{ such that } A \text{ and } B \text{ are independent}

i.e. P(A∩B)=P(A) P(B)\text{i.e. } P(A \cap B) = P(A)\,P(B)

P(A)=410=25P(A) = \dfrac{4}{10} = \dfrac{2}{5}

let n(B)=k,P(B)=k10\text{let } n(B) = k,\quad P(B) = \dfrac{k}{10}

A,B independent  ⟺  P(A∩B)=P(A) P(B)A,B \text{ independent} \iff P(A \cap B) = P(A)\,P(B)

  ⟺  P(B∣A)=P(B)\iff P(B \mid A) = P(B)

P(A) P(B)=25⋅k10=k25P(A)\,P(B) = \dfrac{2}{5}\cdot\dfrac{k}{10} = \dfrac{k}{25}

P(A∩B)=∣A∩B∣10P(A \cap B) = \dfrac{|A \cap B|}{10}

⇒∣A∩B∣=10k25=2k5\Rightarrow |A \cap B| = \dfrac{10k}{25} = \dfrac{2k}{5}

∣A∩B∣=2k5∈Z ⇒ k=5 or 10|A \cap B| = \dfrac{2k}{5} \in \mathbb{Z} \ \Rightarrow\ k = 5 \ \text{or}\ 10

k=5: ∣A∩B∣=2 (≤4)✓k=5:\ |A \cap B| = 2 \ (\le 4)\quad \checkmark

k=10: ∣A∩B∣=4 (≤4)✓k=10:\ |A \cap B| = 4 \ (\le 4)\quad \checkmark

k=2,4,8 or 3,6,9 or 4,8: 2k5∉Zk=2,4,8 \ \text{or}\ 3,6,9 \ \text{or}\ 4,8:\ \dfrac{2k}{5} \notin \mathbb{Z}

n(B)=5 or 10 ⇒ Option (4)n(B) = 5 \ \text{or}\ 10 \ \Rightarrow\ \text{Option } (4)

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