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JEE Advanced 2019 · Complex Numbers and Quadratic Equations

set {∣a+bω+cω2∣2:a,b,c distinct non-zero integers}\left\{\left|a + b\omega + c\omega^{2}\right|^{2} : a,b,c \text{ distinct non-zero integers}\right\} equals ‾\underline{\hspace{2cm}}.

Answer: 33

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Written solution

set {|a + bω + cω²|² : a,b,c distinct non-zero integers} equals underlinehspace2cm.

ω3=1,1+ω+ω2=0\omega^3 = 1, \quad 1 + \omega + \omega^2 = 0

a, b, c distinct non-zero integersa,\ b,\ c \text{ distinct non-zero integers}

z=a+bω+cω2z = a + b\omega + c\omega^{2}

To find: the set of all possible values of ∣z∣2\text{To find: the set of all possible values of } |z|^{2}

1. ∣z∣2 via zzˉ1.\ |z|^{2} \text{ via } z\bar z

2. use 1+ω+ω2=02.\ \text{use } 1+\omega+\omega^2=0

3. sum of squares; write the set3.\ \text{sum of squares; write the set}

1+ω+ω2=01 + \omega + \omega^2 = 0

∣z∣2=zzˉ,zˉ=a+bω2+cω|z|^{2} = z\bar{z}, \quad \bar{z} = a + b\omega^{2} + c\omega

∣z∣2=(a+bω+cω2)(a+bω2+cω)|z|^{2} = (a+b\omega+c\omega^{2})(a+b\omega^{2}+c\omega)

a⋅a=a2,(bω)(bω2)=b2ω3=b2,(cω2)(cω)=c2ω3=c2a\cdot a = a^2,\quad (b\omega)(b\omega^2) = b^2\omega^3 = b^2,\quad (c\omega^2)(c\omega) = c^2\omega^3 = c^2

cross terms=(ab+bc+ca)(ω+ω2)\text{cross terms} = (ab+bc+ca)(\omega+\omega^2)

∣z∣2=a2+b2+c2−ab−bc−ca|z|^{2} = a^2+b^2+c^2 - ab - bc - ca

∣z∣2=12[(a−b)2+(b−c)2+(c−a)2]|z|^{2} = \tfrac{1}{2}\left[(a-b)^2+(b-c)^2+(c-a)^2\right]

a,b,c distinct⇒(a−b),(b−c),(c−a)≠0a,b,c \text{ distinct} \Rightarrow (a-b),(b-c),(c-a) \neq 0 (a−b)+(b−c)+(c−a)=0(a-b)+(b-c)+(c-a)=0

min⁡=12(1+1+4)=3(e.g. a,b,c=2,3,4)\min = \tfrac{1}{2}(1+1+4) = 3 \quad (\text{e.g. } a,b,c = 2,3,4)

(a,b,c)=(1,2,4): ∣z∣2=12(1+4+9)=7(a,b,c)=(1,2,4):\ |z|^{2} = \tfrac{1}{2}(1+4+9) = 7

∣z∣2≡a2+b2+c2+2(ab+bc+ca)=(a+b+c)2(mod3)|z|^{2} \equiv a^2+b^2+c^2+2(ab+bc+ca) = (a+b+c)^2 \pmod 3

⇒∣z∣2≡0 or 1(mod3)\Rightarrow |z|^{2} \equiv 0 \text{ or } 1 \pmod 3

x=a−b, y=b−c⇒∣z∣2=x2+xy+y2x=a-b,\ y=b-c \Rightarrow |z|^{2} = x^2+xy+y^2

xy(x+y)≠0xy(x+y) \neq 0

any x2+xy+y2, xy(x+y)≠0, is attainable (choose c large)\text{any } x^2+xy+y^2,\ xy(x+y)\neq0, \text{ is attainable (choose } c \text{ large)}

{3, 7, 12, 13, 19, 21, 27, 28, … }\{3,\,7,\,12,\,13,\,19,\,21,\,27,\,28,\,\dots\}

{ x2+xy+y2:x,y∈Z, xy(x+y)≠0 }\boxed{\left\{\,x^2+xy+y^2 : x,y \in \mathbb{Z},\ xy(x+y) \neq 0\,\right\}}

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