arthham

JEE Advanced 2023 · Probability (Class 12)

Two distinct points are chosen randomly out of the points A1,A2,…,A49A_1, A_2, \ldots, A_{49}. Let pp be the probability that they are friends. Then the value of 7p7p is

Answer: 0.500.50

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Written solution

Points A1,A2,…,A49 are given\text{Points } A_1, A_2, \ldots, A_{49} \text{ are given}

2 distinct points chosen at random (unordered)2 \text{ distinct points chosen at random (unordered)}

p=P(the two chosen points are friends)p = P(\text{the two chosen points are friends})

To find: 7p\text{To find: } 7p

Ai,Aj are friends  ⟺  i+j≡0(mod7)A_i, A_j \text{ are friends} \iff i + j \equiv 0 \pmod 7

Total outcomes=(492)=49×482=1176\text{Total outcomes} = \binom{49}{2} = \dfrac{49 \times 48}{2} = 1176

Residues of 1,…,49(mod7): each of 0,1,…,6 appears 7 times\text{Residues of } 1, \ldots, 49 \pmod 7:\ \text{each of } 0, 1, \ldots, 6 \text{ appears } 7 \text{ times}

Both≡0(mod7):(72)=21\text{Both} \equiv 0 \pmod 7:\quad \binom{7}{2} = 21

Opposite residues {a,7−a}:3×(7×7)=147\text{Opposite residues } \{a, 7-a\}:\quad 3 \times (7 \times 7) = 147

Friendly pairs=21+147=168\text{Friendly pairs} = 21 + 147 = 168

p=1681176=17p = \dfrac{168}{1176} = \dfrac{1}{7}

7p=7×17=17p = 7 \times \dfrac{1}{7} = 1

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